SOLUTION: ln(x+1)
_______ > 0
1+ln(x)
i put the inequality like that so its easier to see it,but can be written this way
ln(x+1)/1+ln(x)>0
the solution is ]1/e,+oo[
Question 1064306: ln(x+1)
_______ > 0
1+ln(x)
i put the inequality like that so its easier to see it,but can be written this way
ln(x+1)/1+ln(x)>0
the solution is ]1/e,+oo[ Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! (ln(x+1)) / (1+ln(x)) > 0
:
multiply both sides of > by (1+ln(x))
:
(1+ln(x)) * (ln(x+1)) > 0
:
divide both sides of > by (ln(x+1)), assuming x > 0
:
1 + ln(x) > 0
:
apply definition of logarithm
:
x > 1/e
:
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interval notation (1/e, +infinity)
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