SOLUTION: In a survey of 100 out patients who reported at a hospital on a day,it was found that 70complained of fever, 50 had stomach troubles and 30 were injured. The entire 100 patients ha
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Question 1064285: In a survey of 100 out patients who reported at a hospital on a day,it was found that 70complained of fever, 50 had stomach troubles and 30 were injured. The entire 100 patients had one or more of the complaints, 44had exactly two of them. How many patients had three of them Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! 100 patients had 150 complaints among them.
44 had two complaints or 88 complaints.
That leaves 56 patients to have 62 complaints.
Patients with complaints have 3.
That would be 3 patients.
53 have 1 complaint=53
44 have 2 complaints=88
3 have 3 complaints=9
add up to 150.
a+2b+3c=150
a+2*44+3c=150
a+3c=62; a=62-3c, substitute below
a+b+c=100
62-3c+44+c=100
-2c=-6
c=3
