SOLUTION: If an object is propelled upward from a height of s feet at an initial velocity of v feet per​ second, then its height h after t seconds is given by the equation h=−16t
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Question 1064121: If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h=−16t^2+vt+s, where h is in feet. If the object is propelled from a height of 88 feet with an initial velocity of 96 feet per second, its height h is given by the equation h=−16t^2+96t+8.
After how many seconds is the height 148 feet? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! h=−16t^2+96t+8.
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I'll assume you meant 88 feet.
h=−16t^2+96t+88 = 148
Solve for t.
2 values for t, ascending and descending.
