SOLUTION: Please help me in this equation: ln(x+1)/1+lnx >0 And if possible this one too: (4-x2).ln(2x^2+x)=0 Thats all, regards

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Please help me in this equation: ln(x+1)/1+lnx >0 And if possible this one too: (4-x2).ln(2x^2+x)=0 Thats all, regards      Log On


   

Question 1064114: Please help me in this equation:
ln(x+1)/1+lnx >0
And if possible this one too:
(4-x2).ln(2x^2+x)=0
Thats all, regards
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me in this equation:
ln(x+1)/1+lnx >0
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It's not an equation, it's an inequality.
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Is it ln%28x%2B1%29%2F1%2Bln%28x%29+%3E0+ ?
Or ln%28x%2B1%29%2F%281%2Bln%28x%29%29+%3E0+ ?
Parentheses are free, use some.
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And if possible this one too:
(4-x2).ln(2x^2+x)=0
If you mean %284-x%5E2%29%2Aln%282x%5E2%2Bx%29=0
Use * (Shift 8) for multiply.
%284-x%5E2%29%2Aln%282x%5E2%2Bx%29=0
4 - x^2 = 0
x = -2, +2
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ln%282x%5E2%2Bx%29=0
ln%282x%5E2%2Bx%29+=+ln%281%29
2x^2 + x = 1
Solve the quadratic for x
Check that the solutions are valid.