SOLUTION: At a super market flour was sold in 12 kg.and 15 kg bags.a baker found that by buying them in 12 kg bags he would need to get 2 more bags than if he were to buy them in 15 kg bags.

Algebra ->  Divisibility and Prime Numbers -> SOLUTION: At a super market flour was sold in 12 kg.and 15 kg bags.a baker found that by buying them in 12 kg bags he would need to get 2 more bags than if he were to buy them in 15 kg bags.      Log On


   



Question 1064108: At a super market flour was sold in 12 kg.and 15 kg bags.a baker found that by buying them in 12 kg bags he would need to get 2 more bags than if he were to buy them in 15 kg bags.the least amount of flour that the baker was buying is what?
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
let x = the number of 15 kg bags.
let x + 2 = the number of 12 kg bags.

you have 12 * (x + 2) = 15 * x

simplify to get 12x + 24 = 15x

solve for x to get x = 8.

when x = 8, x + 2 = 10

15 * 8 = 120

12 * 10 = 120

8 bags of 15 kg each is equal to 10 bags of 12 kg each.

i believe, that's not just the least amount of flour the baker is buying, but it's the only amount of flour that the baker is buying, since the graphs of these two equations are straight lines and will only intersect at x = 8.