SOLUTION: Three angles of a polygon are 125°,140°and 160°.The remaining angles are 145°each.Calculate the sum of the interior angles of the polygon
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Question 1064094: Three angles of a polygon are 125°,140°and 160°.The remaining angles are 145°each.Calculate the sum of the interior angles of the polygon Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Three angles of a polygon are 125°,140°and 160°.The remaining angles are 145°each. Calculate the sum of the interior angles of the polygon
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125 + 140 + 160 = 425 degs
The sum has to be an integral multiple of 180 --> the # of 145 deg angles is an odd number.
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n = # of 145 angles
--> n + 3 sides and angles
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425 + n*145 = (n+1)*180 = 180n + 180
245 = 35n
n = 7
# of sides = 10
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Sum = 8*180 = 1440 degrees
