SOLUTION: Find the domain of the function. {{{g(x)= x/x^2-64}}}}

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Question 1064038: Find the domain of the function. g%28x%29=+x%2Fx%5E2-64}
Found 2 solutions by ikleyn, solver91311:
Answer by ikleyn(52752) About Me  (Show Source):
You can put this solution on YOUR website!
.
The domain is the set of all real numbers, where the denominator is not zero:


x^2 =/= 64,


i.e.  x =/= 8  and  x =/= -8.

Notice I edited your writing.



Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


The domain of the function as you wrote it is all real numbers except 0. However, I think you probably meant to write



In that case, the domain is all real numbers except the two zeros of the polynomial in the denominator. In other words, solve:



to find the two values to exclude from the domain.

If this is the case, you should have used parentheses to include the -64 in the denominator. That is x/(x^2 - 64) inside of the curly braces would have rendered like this:

x%2F%28x%5E2+-+64%29

John

My calculator said it, I believe it, that settles it