Question 1064010: Please show the complete solution to these two related problems;
Emily rows six miles downstream in 1 hour and her friend Ashley,rowing 1 mile per hour faster,completes the return trip in two hours.
1) Find the speed of the current (c) and each girl's rowing speed.
2) If Emily and Ashley were rowing separately,who would complete their first and by how long? Round to the nearest hundredth,if necessary.
Answer by jorel1380(3719)   (Show Source):
You can put this solution on YOUR website! 1)Let r be Emily's rowing speed; then Ashley's rowing speed is r+1. And let the speed of the current be c. Then:
6/r+c=1 and
6/(r+1)-c=2
So:
r+c=6 and
2r+2-2c=6, or 2r-2c=4
2r+2c=12
2r-2c=4
4r=16
r=4
Emily's rowing speed is 4 mph; the current is 2 mph. And Ashley's rowing speed is 5 mph.
2)Emily's total time:
6/4+2 + 6/4-2=6/6+6/2=4 hours
Ashley's total time:
6/7+6/3=2&6/7 hours
4-2.8571428571428571428571428571429=1.142857 hours that Ashley would finish ahead of Emily. ☺☺☺☺
|
|
|
