SOLUTION: What are three consecutive integers whose product is 693 more than their sum?

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Question 1063664: What are three consecutive integers whose product is 693 more than their sum?
Found 2 solutions by josgarithmetic, Alan3354:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Let n be any integer.
Three consecutive integers: system%28n%2Cn%2B1%2Cn%2B2%29

n%2Bn%2B1%2Bn%2B2%2B693=n%28n%2B1%29%28n%2B2%29

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
What are three consecutive integers whose product is 693 more than their sum?
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root%283%2C693%29 =~ 9, the middle integer
--> 8, 9 & 10
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If you do it the hard way:
(n-1)*n*(n+1) = n-1 + n + n+1 + 693
n^3 - n = 3n + 693
n^3 - 4n - 693 = 0
n = 9