SOLUTION: Construct a system of two linear equations where (-5,4) is a solution to the first equation but not to the second equation, and where (5,-2) is a solution to your system. Step 1 pl
Question 1063509: Construct a system of two linear equations where (-5,4) is a solution to the first equation but not to the second equation, and where (5,-2) is a solution to your system. Step 1 plot the points given to you and write the equation of that line. Call it L1. Step 2 on the graph draw a second line that will create a system of equations with the desired solution step3 writethe equation of your line call it L2. Follow up questions 1 explain how graph shows your system satisfies the required conditions 2should u have the same equation as your partner for L1 explain why or why not 3 should u have the same equation as your partner for L2 explain why or why not Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Construct a system of two linear equations where (-5,4) is a solution to the first equation but not to the second equation, and where (5,-2) is a solution to your system. Step 1 plot the points given to you and write the equation of that line. Call it L1. Step 2 on the graph draw a second line that will create a system of equations with the desired solution step3 writethe equation of your line call it L2.
---------------------------------
Follow up questions 1 explain how graph shows your system satisfies the required conditions 2 should u have the same equation as your partner for L1 explain why or why not 3 should u have the same equation as your partner for L2 explain why or why not.
-----
Equation of line thru (-5,4) and (5,-2)
slope = (4--2)/(-5-5) = 6/-10 = -3/5
Form:: y = mx + b
4 = (-3/5)(-5) + b
4 = 3 + b
b = 1
L1:: y = (-3/5)x + 1
--------------------
Equation of L2::
y = -2
----------------
Graph::
----------------
Cheers,
Stan H.
---------------
(