SOLUTION: lucia travels from point A to point B at 100km/h. Jane leaves at the same time as Lucia, travelling from point B to point A at 50km/h. The distance from A to B is 100km.How long af

Algebra ->  Test -> SOLUTION: lucia travels from point A to point B at 100km/h. Jane leaves at the same time as Lucia, travelling from point B to point A at 50km/h. The distance from A to B is 100km.How long af      Log On


   



Question 1063502: lucia travels from point A to point B at 100km/h. Jane leaves at the same time as Lucia, travelling from point B to point A at 50km/h. The distance from A to B is 100km.How long after the two leave will they meet on the road?
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
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lucia travels from point A to point B at 100km/h. Jane leaves at the same time as Lucia, travelling from point B to point A at 50km/h.
The distance from A to B is 100km.How long after the two leave will they meet on the road?
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time = 100%2F%28100%2B50%29 = 100%2F150 = 2%2F3 of an hour = 40 minutes.


Initial distance between them is 100 km.


Since they move toward each other, the distance decreases at the rate of 100 km/h + 50 km/h = 100 km/h.


Therefore, time = Distance%2FRate, as I did above.