SOLUTION: Newgy has twice as many nickels as dimes,and four times as many pennies as nickels. If she has a total of $2.80, how many of each coin does she have?

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Question 1063402: Newgy has twice as many nickels as dimes,and four times as many pennies as nickels. If she has a total of $2.80, how many of each coin does she have?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
p pennies
n nickels
d dimes
-
system%28n%2Fd=2%2Cp%2Fn=4%2C0.01p%2B0.05n%2B0.1d=2.80%29

system%28d=n%2F2%2Cp=4n%2Cp%2B5n%2B10d=280%29

d and p are in terms of n.

Substitution gives a single equation in just one unknown variable:
highlight_green%284n%2B5n%2B10%28n%2F2%29=280%29
14n=280
highlight%28n=20%29

The other two follow easily.

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!
Newgy has twice as many nickels as dimes,and four times as many pennies as nickels. If she has a total of $2.80, how many of each coin does she have?
Let number of dimes be D

Then number of nickels = 2D

Number of pennies = 4(2D), or 8D

We then get: .1D + .05(2D) + .01(8D) = 2.8

.1D + .1D + .08D = 2.8

.28D = 2.8

D, or number of dimes = highlight_green%28matrix%281%2C3%2C+2.8%2F.28%2C+or%2C+10%29%29

Number of nickels: highlight_green%28matrix%281%2C3%2C+2%2810%29%2C+or%2C+20%29%29

Number of pennies: highlight_green%28matrix%281%2C3%2C+8%2810%29%2C+or%2C+80%29%29

It's as easy as that....nothing COMPLEX and/or CONFUSING!