SOLUTION: I have another tough word problem that I hope someone can show me the solutions .
A kicker punts a football from 3 feet above the ground with an initial velocity of 47 feet per
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: I have another tough word problem that I hope someone can show me the solutions .
A kicker punts a football from 3 feet above the ground with an initial velocity of 47 feet per
Log On
Question 1063233: I have another tough word problem that I hope someone can show me the solutions .
A kicker punts a football from 3 feet above the ground with an initial velocity of 47 feet per second.
1) Write an equation that gives the height (in feet) of the football as a function of the time (in seconds) since it was punted. 2) Find the height (in feet) of the football 2 seconds after the punt. And,3) Calculate how many seconds after the punt the ball would hit the ground.
Wow! I certainly owe a huge THANK YOU to the person able to help me on this one. Answer by ikleyn(52781) (Show Source):
You can put this solution on YOUR website! .
I have another tough word problem that I hope someone can show me the solutions .
A kicker punts a football from 3 feet above the ground with an initial velocity of 47 feet per second.
1) Write an equation that gives the height (in feet) of the football as a function of the time (in seconds) since it was punted.
h(t) = .
h is the height above the ground.
I assume (! You didn't say it) that the velocity is VERTICAL velocity (directed upward)
2) Find the height (in feet) of the football 2 seconds after the punt.
Substitute t= 2 into this equation.
3) Calculate how many seconds after the punt the ball would hit the ground.
For it, solve the equation h(t) = 0 for t, which is the same as = 0.