SOLUTION: How do I work these problems out?
1. A study of 40 people found that they could do on the average 15 pull ups with a standard deviation of .6. Find the 99% confidence interval f
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-> SOLUTION: How do I work these problems out?
1. A study of 40 people found that they could do on the average 15 pull ups with a standard deviation of .6. Find the 99% confidence interval f
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Question 1063136: How do I work these problems out?
1. A study of 40 people found that they could do on the average 15 pull ups with a standard deviation of .6. Find the 99% confidence interval for the mean of the population.
2. A study of 50 pizza delivery workers found that they could make 6 deliveries per hour with a standard deviation of 1. Find the 95% confidence interval of the mean for all pizza delivery workers.
3. A random sample of 50 households showed that the average number of TVs in each household is 2.3 with a standard deviation of .4. Find the 90% confidence level for the average number of TVs in every household in the population.
4. A researcher revealed that the average number of people who have a driver's license out of a sample of 100 people is 1.5 with a standard deviation of .3. Find the 80% confidence interval for the mean of the population.
5. The following random sample was selected: 4, 6, 3, 5, 9, 3. Find the 95% confidence interval for the mean of the population.
6.In a sample of 35 high school seniors, 14 of them are attending college in the fall. Find the 95% confidence interval for the true proportion of high school seniors that will attend college in the fall from the population.
7. In a sample of 200 people, 76 people would rather work out at home than in a gym. Find the 99% confidence interval for the true proportion of people who would rather work out at home than in a gym for the entire population.
0.76 +/- (2.575)(√0.76)/(-0.24)/√200
0.71323264675
0.713 - .5/1000 = 0.7125 - .5/.0005 = 0.712
0.713 + .5/1000 = 0.7125 +.5/.0005 = 0.714
The 99% confidence interval is +/- 0.76.
71.2% - 71.4%
8. A study found that out of 300 people 60% of them prefer to eat hamburgers rather than hot dogs. Find the 95% confidence interval for the true proportion of people who prefer to eat hamburgers rather than hot dogs in the entire population.
