SOLUTION: The second of two numbers is 3 times the first. Eight times the sum of the first number and -2 is equal to the second number decreased by 11. Find the numbers

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Question 1063080: The second of two numbers is 3 times the first. Eight times the sum of the first number and -2 is equal to the second number decreased by 11. Find the numbers
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +n+ = the 1st number
+3n+ = the 2nd number
+8%2A%28+n+-+2+%29+=+3n+-+11+
+8n+-+16+=+3n+-+11+
+5n+=+16+-+11+
+5n+=+5+
+n+=+1+
and
+3n+=+3+
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The numbers are 1 and 3
check:
+8%2A%28+n+-+2+%29+=+3n+-+11+
+8%2A%28+1+-+2+%29+=+3%2A1+-+11+
+-8+=+-8+
OK