SOLUTION: Five times the second of three consecutive odd integers is thirteen less than three times the sum of the first and third integers. Find the smallest odd integer

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Question 1063054: Five times the second of three consecutive odd integers is thirteen less than three times the sum of the first and third integers. Find the smallest odd integer
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the consecutive odd integers be:
+n+, +n+%2B+2+, +n+%2B+4+
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+5%2A%28+n+%2B+2+%29+=+3%2A%28+n+%2B+n+%2B+4+%29+-+13+
+5n+%2B+10+=+6n+%2B+12+-+13+
+n+=+10+%2B+13+-+12+
+n+=+23+-+12+
+n+=+11+
The smallest odd integer is 11
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check:
+5%2A%28+n+%2B+2+%29+=+3%2A%28+n+%2B+n+%2B+4+%29+-+13+
+5%2A13+=+3%2A%28+11+%2B+15+%29+-+13+
+65+=+3%2A26+-+13+
+65+=+78+-+13+
+65+=+65+
OK