SOLUTION: 2.on the last day of his vacation a backpacker walks 40 miles, which raises his daily mileage on his backpacking vacation from 32 miles to 33 miles. how far would he have needed to

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Question 1063022: 2.on the last day of his vacation a backpacker walks 40 miles, which raises his daily mileage on his backpacking vacation from 32 miles to 33 miles. how far would he have needed to walk on the final day to bring his average daily mileage up to 35 miles?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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2.on the last day of his vacation a backpacker walks 40 miles, which raises his daily mileage on his backpacking vacation from 32 miles to 33 miles.
how far would he have needed to walk on the final day to bring his average daily mileage up to 35 miles?
:
let n = no. days he walked prior to the last day
%28%2832n%2B40%29%29%2F%28%28n%2B1%29%29 = 33
32n + 40 = 33(n+1)
32n + 40 = 33n + 33
40 - 33 = 33n - 32n
7 = n
He walked 7 days prior to the last day
:
let m = no. mi he has to walk on the last day to average 35 mi
%28%287%2832%29+%2B+m%29%29%2F8 = 35
%28%28224+%2B+m%29%29%2F8 = 35
224 + m = 8 * 35
m = 280 - 224
m = 56 mi he would have to walk on the last day to average 35 mi for the 8 days