SOLUTION: csc Θ = {{{ sqrt( 5 ) }}}, so what is cot Θ? A.) {{{ sqrt( 5 )/5 }}} B.) {{{ 1/2 }}} C.) {{{ 5 }}} D.) {{{ 2 }}} Thanks.

Algebra ->  Test -> SOLUTION: csc Θ = {{{ sqrt( 5 ) }}}, so what is cot Θ? A.) {{{ sqrt( 5 )/5 }}} B.) {{{ 1/2 }}} C.) {{{ 5 }}} D.) {{{ 2 }}} Thanks.       Log On


   

Question 1062961: csc Θ = +sqrt%28+5+%29+, so what is cot Θ?
A.) +sqrt%28+5+%29%2F5+
B.) +1%2F2+
C.) +5+
D.) +2+
Thanks.
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
csc(t) = sqrt( 5 ) so what is cot(t) ?
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By definition, csc = r/y
Since csc(t) = sqrt(5), r = sqrt(5) and y = 1
Then x = sqrt[(sqrt(5))^2-1^2] = sqrt[5-1] = 2
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Ans:: Then cot(t) = y/x = 1/2
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Cheers,
Stan H.
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A.) +sqrt%28+5+%29%2F5+
B.) +1%2F2+
C.) +5+
D.) +2+

Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!

csc Θ = +sqrt%28+5+%29+, so what is cot Θ?
A.) +sqrt%28+5+%29%2F5+
B.) +1%2F2+
C.) +5+
D.) +2+
Thanks.
highlight_green%28matrix%281%2C4%2C+2%2C+or%2C+CHOICE%2C+%22D.%29%22%29%29