SOLUTION: When tan(theta) + sec(theta) = x show that sin(theta) = (x^2-1)/(x^2+1)

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Question 1062923: When tan(theta) + sec(theta) = x show that sin(theta) = (x^2-1)/(x^2+1)
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

Given tan%28theta%29+%2B+sec%28theta%29%22%22=%22%22x show that sin%28theta%29%22%22=%22%22%28x%5E2-1%29%2F%28x%5E2%2B1%29 

We begin by proving the converse.  That is first we prove:

Given sin%28theta%29%22%22=%22%22%28x%5E2-1%29%2F%28x%5E2%2B1%29 show that tan%28theta%29+%2B+sec%28theta%29%22%22=%22%22x

[IOW, we start with what we have to prove, prove what was given,
and then we reverse the proof.]

Draw a right triangle containing angle theta with opposite
side x²-1 and hypotenuse x²+1, 



and we find what the adjacent side 
must equal using the Pythagorean theorem:

c%5E2=a%5E2%2Bb%5E2
%28x%5E2%2B1%29%5E2=a%5E2%2B%28x%5E2-1%29%5E2
%28x%5E2%2B1%29%5E2-%28x%5E2-1%29%5E2=a%5E2
factor the left side as the difference of squares:

%28+x%5E2%2B1-x%5E2%2B1+%29%28+x%5E2%2B1%2Bx%5E2-1+%29=a%5E2
%282%5E%22%22%29%282x%5E2+%29=a%5E2
4x%5E2+=a%5E2
2x=a

So we complete the right triangle with adjacent side 2x:



From that triangle we can prove what was given: 

tan%28theta%29+%2B+sec%28theta%29%22%22=%22%22x

%28x%5E2-1%29%2F%282x%29%2B%28x%5E2%2B1%29%2F%282x%29%22%22=%22%22
%28x%5E2-1%2Bx%5E2%2B1%29%2F%282x%29%22%22=%22%22
%282x%5E2%29%2F%282x%29%22%22=%22%22
x

So now that we have proved the converse of the problem,
we can reverse the proof:

-----------------------------------

Given tan%28theta%29+%2B+sec%28theta%29%22%22=%22%22x,
reversing the above steps:

x%22%22=%22%22
%282x%5E2%29%2F%282x%29%22%22=%22%22
%28x%5E2-1%2Bx%5E2%2B1%29%2F%282x%29%22%22=%22%22
%28x%5E2-1%29%2F%282x%29%2B%28x%5E2%2B1%29%2F%282x%29%22%22=%22%22

From that and tan%28theta%29+%2B+sec%28theta%29%22%22=%22%22x
we can draw the right triangle:



Then from that right triangle, it follows that

sin%28theta%29%22%22=%22%22%28x%5E2-1%29%2F%28x%5E2%2B1%29

Edwin