SOLUTION: a bus leaves a station at 1 p.m traveling west at an average rate of 44 mile an hour. one hour later a second bus leaves the same station traveling east at a rate of 48 mile an ho
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Question 106286: a bus leaves a station at 1 p.m traveling west at an average rate of 44 mile an hour. one hour later a second bus leaves the same station traveling east at a rate of 48 mile an hour. at what time will the two buses be 274 mile apart Answer by ptaylor(2198) (Show Source):
You can put this solution on YOUR website! distance(d) equals rate(r) times time(t) or d=rt; t=d/r and r=d/t
Let t=time that elapses until the two vehicles are 274 mi apart
When Bus#2 leaves, Bus#1 has already travelled 44*1 or 44 miles
Distance Bus#1 travels=44+44t
Distance Bus#2 travels=48t
Now we are told that the distance Bus#1 travels plus the distance Bus#2 travels equals 274 mi, or:
44+44t+48t=274 subtract 44 from both sides
44-44+44t+48t=274-44 collect like terms
92t=230 divide both sides by 92
t=2.5 hours------------------------time that elapses until the two vehicles are 274 mi apart
Bus#2 leaves at 2:00pm. So 2:00pm +2.5 hours=4:30pm the time when the two busses are 274 mi apart
CK
44+44*2.5=154 mi
48*2.5=120
154+120=274
274=274
Hope this helps---ptaylor
