SOLUTION: A rectangle has a length 5 feet greater than its width. If both dimensions are increased by 2 feet, write an expression for the difference in the areas of the rectangles
Algebra ->
Rectangles
-> SOLUTION: A rectangle has a length 5 feet greater than its width. If both dimensions are increased by 2 feet, write an expression for the difference in the areas of the rectangles
Log On
Question 1062845: A rectangle has a length 5 feet greater than its width. If both dimensions are increased by 2 feet, write an expression for the difference in the areas of the rectangles Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! Let w be the width of the smaller rectangle. Then its' length is w+5, so its' area is w(w+5). Then the larger rectangle's width is w+2, and its length is w+5+2, or w+7. So:
(w+2)(w+7)-w(w+5)=?
w²+9w+14-w²-5w=?
4w+14 is the difference between the two rectangles. ☺☺☺☺
