SOLUTION: From a two place digit number 5times tens' digit and 3times unit's digit is subtracted leaving a remainder of 32.The tens' digit less the units digit is 4. Find the number.

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Question 1062830: From a two place digit number 5times tens' digit and 3times unit's digit is subtracted leaving a remainder of 32.The tens' digit less the units digit is 4. Find the number.
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
t for the TENS digit and u for the UNITS or ONES digit.
The original number is 10t%2Bu.

The description changed into equations is the system
system%28%2810t%2Bu%29-5t-3u=32%2Cu-t=4%29
This interpretation will not work, giving you instead a non-digit result.


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The tens' digit less the units digit is 4.
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In case that part of the description is unclear, this part could mean abs%28u-t%29=4, so two choices are possible. Here is the choice which will work:
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system%28%2810t%2Bu%29-5t-3u=32%2Ct-u=4%29

10t-5t%2Bu-3u=32
5t-2u=32
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use second equation solved for t,
t=u%2B4 and substitute into "first" equation.
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5%28u%2B4%29-2u=32
5u%2B20-2u=32
5u-2u%2B20=32
3u=12
highlight%28u=4%29
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Use this found u value to evaluate t.
t=u%2B4
t=4%2B4
highlight%28t=8%29
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Original Nummber highlight%2810%2A8%2B4=84%29.