SOLUTION: The length of a rectangle is twice the width. The perimeter is 84 cm more than the width. Make a diagram and find the rectangle's dimensions.

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: The length of a rectangle is twice the width. The perimeter is 84 cm more than the width. Make a diagram and find the rectangle's dimensions.      Log On


   

Question 106283This question is from textbook Algabra Structure and Method
: The length of a rectangle is twice the width. The perimeter is 84 cm more than the width. Make a diagram and find the rectangle's dimensions. This question is from textbook Algabra Structure and Method

Answer by elima(1433) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is twice the width. The perimeter is 84 cm more than the width.
I'll go ahead and find the dimensions;
L=2W
2(2W)+2W=84
4W+2W=84
6W=84
w=14
L=2(14)=28
:)