SOLUTION: The length and width of a square are increased by 6 ft and 8 ft, respectively. The result is a rectangle whose area is 188 sq. ft more than the area of the square. Determine the le

Algebra ->  Rectangles -> SOLUTION: The length and width of a square are increased by 6 ft and 8 ft, respectively. The result is a rectangle whose area is 188 sq. ft more than the area of the square. Determine the le      Log On


   

Question 1062810: The length and width of a square are increased by 6 ft and 8 ft, respectively. The result is a rectangle whose area is 188 sq. ft more than the area of the square. Determine the length pf the side of the square.
Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
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(W+6)*(W+8) - W^2 = 188,

W^2 + 6W + 8W + 48 - W^2 = 188,

14W = 188-48,

14W = 140,

W = 10.

Answer. The side of the square is of 10 units long.