SOLUTION: Jane has Php 6.00 consisting of 10 cents and 25 cents coins.The number of 10 cents coins is y.If she has a total of 30 coins,how many coins of each denomination are there?
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Question 1062774: Jane has Php 6.00 consisting of 10 cents and 25 cents coins.The number of 10 cents coins is y.If she has a total of 30 coins,how many coins of each denomination are there?
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If y = number of 10 cent coins, (30-y) is the number of 25 cent coins, so we can write:
10y + 25(30-y) = 600 (expressed in cents)
10y + 750 - 25y = 600
-15y = -150
y = -150/-15 = 10
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Ans: There are 10 ten cent coins and 20 twenty-five cent coins
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Check:
10(10) + 20(25) = 100 + 500 = 600 (ok)