Question 1062664: Please could be found the rule of such a sequence:
72, 12, 6, 4, 3, 2, 2 ?
Please don't modify the given series.
The similar problem with 79, 24, 12... is much easier.
What might be the next number?
Thanks in advance,
Vlad
Found 2 solutions by Edwin McCravy, Alan3354:
Answer by Edwin McCravy(20064)   (Show Source):
You can put this solution on YOUR website!
The recursion formula is:
a(n) = a(n-3)/a(n-1)
72, 24, 12, 6, 4, 3, 2, 2, 3/2, 4/3, 3/2
a(4) = a(1)/a(3) = 72÷12 = 6
a(5) = a(2)/a(4) = 24÷6 = 4
a(6) = a(3)/a(5) = 12÷4 = 3
a(7) = a(4)/a(6) = 6÷3 = 2
a(8) = a(5)/a(7) = 4÷2 = 2
a(9) = a(6)/a(8) = 3÷2 = 3/2
a(10) = a(7)/a(9) = 2÷3/2 = 2×(2/3) = 4/3
a(11) = a(8)/a(10) = 2÷4/3 = 2×(3/4) = 3/4
The 9th term, a(9) = 3/2
Edwin
Answer by Alan3354(69443)  (Show Source):
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