SOLUTION: 11/the square root of 3-5. I know that have to multiply by the oppisite which is the square root of 3+5 but I don't know what to do from there.

Algebra ->  Square-cubic-other-roots -> SOLUTION: 11/the square root of 3-5. I know that have to multiply by the oppisite which is the square root of 3+5 but I don't know what to do from there.      Log On


   

Question 106266: 11/the square root of 3-5. I know that have to multiply by the oppisite which is the square root of 3+5 but I don't know what to do from there.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
11/the square root of 3-5. I know that have to multiply by the oppisite which is the square root of 3+5 but I don't know what to do from there.
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[11/sqrt(3)] -5
Rationalize the denominator by multiplying num and denom by sqrt3 to get:
[11sqrt3/3] - 5
= [(11/3)sqrt3] - 5
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If you original problem is the following you do as follows:
11/[sqrt(3)-5}
Rationalize the denominator by multiplying num and denom by [sqrt3 + 5] to get:
[11(sqrt(3)+5]/[3-25]
= [11sqrt(3)+5]/(-22)
= [sqrt(3)+5]/(-2)
= (-1/2)(sqrt(3)+5)
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Cheers,
Stan H.