SOLUTION: Solve the system of equations y = log_2 (2x), y = log_4 x. Write your answers as ordered pairs (x,y). If you find more than one solution, list the solutions in order of increas

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Solve the system of equations y = log_2 (2x), y = log_4 x. Write your answers as ordered pairs (x,y). If you find more than one solution, list the solutions in order of increas      Log On


   

Question 1062622: Solve the system of equations
y = log_2 (2x),
y = log_4 x.
Write your answers as ordered pairs (x,y). If you find more than one solution, list the solutions in order of increasing value of x and separate your answers with semi-colons. So, for example, you would type "(2,2);(4,6)" to say that x=2,y=2 and x=4,y=6 are the two solutions.
Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
y+=+log%282%2C%282x%29%29
y+=+log%284%2Cx%29
---
Since both equal y:
log%282%2C%282x%29%29+=+log%284%2Cx%29
log%282%2C%282x%29%29+=+log%282%2C%282x%29%29
2x = 2x
x = any value > 0
y = log(x)/log(4)


Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!

Solve the system of equations
y = log_2 (2x),
y = log_4 x.
Write your answers as ordered pairs (x,y). If you find more than one solution, list the solutions in order of increasing value of x and separate your answers with semi-colons. So, for example, you would type "(2,2);(4,6)" to say that x=2,y=2 and x=4,y=6 are the two solutions.