SOLUTION: log4(1/8)+log8(1/4)-log2(64)

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Question 1062533: log4(1/8)+log8(1/4)-log2(64)
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Assuming the three different bases are being attempted expressed,

log%284%2C2%5E3%29%2Blog%288%2C2%5E2%29-log%282%2C2%5E6%29

3%2Alog%284%2C2%29%2B2%2Alog%288%2C2%29-6%2Alog%282%2C2%29

------Change Of Base formula

3%2F2%2B2%2F3-6%2A1

9%2F6%2B4%2F6-6

13%2F6-6

%2813-36%29%2F6

highlight%28-23%2F6%29


---
system%28x%3C%3E0%2Cx%3C%3E1%29,
log%28x%2Cx%29=1

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
log4(1/8)+log8(1/4)-log2(64)
Correct answer: highlight_green%28matrix%281%2C3%2C+-+49%2F6%2C+or%2C+-+8%261%2F6%29%29


Student's response
====================================================== TEXT FOLLOWS
please can I see your workings
====================================================== END TEXT


log+%284%2C+%281%2F8%29%29+%2B+log+%288%2C+%281%2F4%29%29+-+log+%282%2C+%2864%29%29



log+%284%2C+%281%2F8%29%29, in EXPONENTIAL form  is:  

log+%288%2C+%281%2F4%29%29, in EXPONENTIAL form  is:  

log+%282%2C+%2864%29%29, in EXPONENTIAL form  is: matrix%281%2C5%2C+2%5Ex+=+64%2C+%22====%3E%22%2C+2%5Ex+=+2%5E6%2C+%22====%3E%22%2C+x+=+6%29 

This gives us:  



You could have also kept it in logs and gotten the same answer.