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| Question 1062396:  a boy has 728 rs denomination of 2 rs notes,5 rs notes and 10 rs nots in the ratio of 3:2:4,respectively. what is the number of notes he has?
 Answer by ikleyn(52879)
      (Show Source): 
You can put this solution on YOUR website! . a boy has 728 rs denomination of 2 rs notes,5 rs notes and 10 rs nots in the ratio of 3:2:4,respectively. what is the number of notes he has?
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The condition says that the numbers of bills are
   3x for 2-rs notes,
   2x for 5-rs notes, and
   4x for 10-rs notes,
where x in an unknown "common measure" of these quantities (of bills).
Then your "value" equation is
  2*(3x) + 5*(2x) + 10*(4x) = 728,   or
  6x + 10x + 40x = 728,   or
  56x = 728.
Then x =  = 13.
Thus there are 3*13 = 39 of the 2-rs notes, 2*13 = 26 of the 5-rs notes and 4*13 = 52 of the 10-rs notes. Solved.
 
 
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