x+y = x×y = x²-y²
Obviously x = 0 = y is a solution.
if x+y = x²-y² then
; ;
But we have to make sure that
For the first case
So one solution is x = y = 0, the obvious one.
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For the second case
For
So a second solution is:
,
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For
So a third solution is:
,
Edwin