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Question 1062372: I am a 4-digit number. My first digit is a cube. My second
digit is prime. My second, third, and fourth digit are
consecutive even numbers. My third digit is a square and my
last digit is thrice my second digit.
Found 2 solutions by Edwin McCravy, MathTherapy: Answer by Edwin McCravy(20060) (Show Source):
You can put this solution on YOUR website! I am a 4 digit number.
Let X's represent the digits:
XXXX
My second, third,fourth digit are consecutive even numbers,
So it's either
X024 or X246 or X468
My third number is a square.
So it can only be
X246
My first digit is a cube.
The only digits that are cubes are 1 and 8. That's
because 13=1 and 23=8
So it either
1246 or 8246
My second digit is prime.
We don't need that information because 2 is prime.
my last digit is thrice my second digit.
We don't need that information either because 6 is
thrice 2.
But we still can't tell whether it's 1246 or 8246.
Edwin
Answer by MathTherapy(10555) (Show Source):
You can put this solution on YOUR website! I am a 4-digit number. My first digit is a cube. My second
digit is prime. My second, third, and fourth digit are
consecutive even numbers. My third digit is a square and my
last digit is thrice my second digit.
1st Digit: Only 2 digits are cubes: 1 and 8, so this can be either.
2nd Digit: With this being PRIME and EVEN, this MUST be 2
3rd and 4th Digits: 4 and 6
Number: 1,246, or 8,246
Clues in first 2 sentences were enough to determine numbers.
This 3rd sentence was UNNECESSARY: My third digit is a square and my last digit is thrice my second digit.
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