SOLUTION: Hi, please help me turn this series into summation notation. Thank you in advance. 1. 2!/7 + 3!/14 + 4!/21 + ... + (n-1)!/7n 2. {{{ -1/5 + 8/25 - 27/125 + 64/625 }}}

Algebra ->  Sequences-and-series -> SOLUTION: Hi, please help me turn this series into summation notation. Thank you in advance. 1. 2!/7 + 3!/14 + 4!/21 + ... + (n-1)!/7n 2. {{{ -1/5 + 8/25 - 27/125 + 64/625 }}}      Log On


   



Question 1062323: Hi, please help me turn this series into summation notation. Thank you in advance.
1. 2!/7 + 3!/14 + 4!/21 + ... + (n-1)!/7n
2. +-1%2F5+%2B+8%2F25+-+27%2F125+%2B+64%2F625+

Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
I like the last term's being (n+1)!
Then I can write sum from n=1 to n of (n+1)!/7n. Is the last term (n+1)!?
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The second term is the sum from n=1 to 4 of -1^(n)*(n^3)/5^(n).
The -1^(n) will alternately be negative-positive, beginning with negative.

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

Hi, please help me turn this series into summation notation. Thank you in advance.
1. 2!/7 + 3!/14 + 4!/21 + ... + (n-1)!/7n
2. +-1%2F5+%2B+8%2F25+-+27%2F125+%2B+64%2F625+

1. sum%28%28n+%2B+1%29%21%2F%287n%29%2C+n+=+1%2C+infinity%29

2. sum%28%28%28-+1%29%5En+%2A+n%5E3%29%2F%285%5En%29%2C+n+=+1%2C+4%29