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Question 1062265: Hello
I really need help with this co ordinate question, it has been bugging me all day.
It is a 2 part question I and I hope you could help, I have asked family members but they do not know.
Here are the equations of four straight lines: y=6 y=2 x=3 x=4
The intersections of these lines form the vertices of a rectangle. What is the perimeter of the triangle.
Part 2 the diagonals of the rectangle have these equations
Y=4x-10
Y=-4x+18
Find the coordinates of the point where these lines intersect.
Thank you for taking your time to have a look st this
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Here are the equations of four straight lines: y=6 y=2 x=3 x=4
The intersections of these lines form the vertices of a rectangle. What is the perimeter of the triangle.
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2 lines are parallel to the y-axis, and 2 to the x-axis.
4-3 = 1 (width)
6-2 = 4 (length)
Makes a rectangle: 1 by 4
P = 2*1 + 2*4 = 10 units.
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Part 2 the diagonals of the rectangle have these equations
Y=4x-10
Y=-4x+18
Find the coordinates of the point where these lines intersect.
Since both equal y,
4x-10 = -4x+18
8x = 28
x = 7/2; y = 4
--> (7/2,4)
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I used the 2 equations you stated. I didn't check them.
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