SOLUTION: Our class began linear applications yesterday. Need help on a math problem as far as setting it up. Problem: Staples charges a base fee of $15 to print cards. It is .12 cent for e

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Question 1062081: Our class began linear applications yesterday. Need help on a math problem as far as setting it up. Problem: Staples charges a base fee of $15 to print cards. It is .12 cent for each card printed. Prints were ordered and paid $45 before taxes. How many cards were ordered to be printed. Thanks for your help and time.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
"It is .12 cent for each card..."
That is 0.12 CENT per CARD, price being a fraction of a cent. As a dollars price, 0.0012 DOLLARS per CARD.

The base price of $15 is for "no cards yet printed", so if you are using x for how many cards and y for the cost, then b is for the base price; and you can use y=mx+b. Fill in the data to express y=0.0012x%2B15.

How many cards were printed, given that y=45? This is the same as, "solve for x, if y=45".
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y-15=0.0012x
%28y-15%29%2F0.0012=x
x=%2845-15%29%2F0.0012
x=30%2F0.0012
highlight%28x=25000%29

Answer by MathTherapy(10549) About Me  (Show Source):
You can put this solution on YOUR website!

Our class began linear applications yesterday. Need help on a math problem as far as setting it up. Problem: Staples charges a base fee of $15 to print cards. It is .12 cent for each card printed. Prints were ordered and paid $45 before taxes. How many cards were ordered to be printed. Thanks for your help and time.
The correct answer depends on whether the card costs 12c, or 0.12c