Question 1062018: Suzy buys 2 shirts and 2 pairs of pants for 42 dollars at the store. Annette buys 3 shirts and 1 pair of pants for 37 dollars.
Create a system of equations that can be used to solve for the cost of the shirts and pants.
A.)2s + 2p = 42
3s + p = 37
B.)2s + 2p = 42
s + 3p = 37
C.)2s + 2p = 37
s + 3p = 42
D.)2s + 2p = 37
3s + p = 42
Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! 2s+2p = 42 (1)
3s+p = 37 (2)
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How much are the pant?
In equation (1), multiply all times 3
In equation (2{, multiply all times 2 and subtract from (1):
6s+6p = 126
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6s+2p = 74
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0s+4p = 52 so now we have zero shirts. Divide both sides by 4 and you get:
p = 13 the pants are 13. And Annette bought 1 pair, and she spent 37. Now, 37-13 = 24 so she paid 24 for 3 shirts or 8 each
Pants cost: 13
Shirts cost: 8
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Check with Suzy:
2 shirts at 8 = 16
2 pants at 13 = 26
Total... . .. .42 Correct, this is how much she spent.
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