SOLUTION: The following information is available. H0 : &#956; &#8805; 220 H1 : &#956; < 220 A sample of 64 observations is selected from a normal population. The sample mean is 2

Algebra ->  Probability-and-statistics -> SOLUTION: The following information is available. H0 : &#956; &#8805; 220 H1 : &#956; < 220 A sample of 64 observations is selected from a normal population. The sample mean is 2      Log On


   



Question 1062013: The following information is available.

H0 : μ ≥ 220

H1 : μ < 220

A sample of 64 observations is selected from a normal population. The sample mean is 215, and the population standard deviation is 15. Conduct the following test of hypothesis using the .025 significance level.

a. Is this a one- or two-tailed test?


One-tailed test
Two-tailed test

b.
What is the decision rule? (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.)

H0 when z <


c.
What is the value of the test statistic? (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)

Value of the test statistic


d. What is your decision regarding H0?


Do not reject
Reject

e. What is the p-value? (Round your answer to 4 decimal places.)

p-value


Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The following information is available.
H0 : μ ≥ 220
H1 : μ < 220
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A sample of 64 observations is selected from a normal population. The sample mean is 215, and the population standard deviation is 15. Conduct the following test of hypothesis using the .025 significance level.
a. Is this a one- or two-tailed test?:: 1-tail (H1 tells you that)
---------------------------------
b. What is the decision rule? (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.)
invNorm(0.025) = -1.96
Reject Ho if z < -1.96
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c. What is the value of the test statistic? (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)
z(215) = (215-220)/[15/sqrt(64)] = -2.6667
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d. What is your decision regarding H0? Reject Ho
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e. What is the p-value? (Round your answer to 4 decimal places.)
p-value = p(z < -2.667) = normalcdf(-100,-2.667) = 0.0038
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Cheers,
Stan H.
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