Find each exact value if 0 < x < pi/2 and 0 < y < pi/2
Cos(x-y) if sinx= 7/25 and cosy= 2/3
This is what I have so far:
cosa•cosB+sina•sinB
(7/25)(2/3)+(7/25)(sqrt5/3)
14/75+7sqrt5/75
14+7sqrt5/75
I'm not sure if I'm finished with the problem or if I have more steps or if I have just done the problem completely wrong. The answer doesn't match the key so I'm curious as to what I'm doing wrong. Thank you!
Find each exact value if  
 cos (A - B) = cos A cos B + sin A sin B ---- Difference of 2 angles' formula
cos (x - y) = cos x cos y + sin x sin y ---- Replacing A with x, and B with y 
It's obvious that we need cos x and sin y
cos (A - B) = cos A cos B + sin A sin B ---- Difference of 2 angles' formula
cos (x - y) = cos x cos y + sin x sin y ---- Replacing A with x, and B with y 
It's obvious that we need cos x and sin y
 We see that a 7-24-25 Pythag triple ensues, and therefore, x = 24
We now have:
We see that a 7-24-25 Pythag triple ensues, and therefore, x = 24
We now have:  
 
 
 
 _____
_____ We now have:
We now have:  cos (x - y) = cos x cos y + sin x sin y now becomes: 
cos (x - y) =
cos (x - y) = cos x cos y + sin x sin y now becomes: 
cos (x - y) =  ------- Substituting
 ------- Substituting  Up to this point, you seem to have gotten
Up to this point, you seem to have gotten  , but
, but  .
You should be able to complete it, now that you know where your mistake was.
Note that since it was stated that:
.
You should be able to complete it, now that you know where your mistake was.
Note that since it was stated that:  , the angles are in the 1st quadrant.
, the angles are in the 1st quadrant.