SOLUTION: Hi I am asking for a tutor to look and see if my answer is correct A certain virus infects one in every 500 people. A test used to detect the virus in a person is positive 90

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Question 1061858: Hi
I am asking for a tutor to look and see if my answer is correct
A certain virus infects one in every 500 people. A test used to detect the virus in a person is positive 90% of the time if the person has the virus and 10% of the time if the person does not have the virus. Let A be the event "the person is infected" and B be the event "the person tests positive."
"What is the probability that a person does not have the virus given that they have tested negative." Of the 180 people who are infected, .1(180)= 18 will text negative. Of the 99800 people who are not infected, .9(99800)= 89820 will test negative. Of the 89820+ 18= 89838 people who tested negative 89820 do not have the virus so the probability a person who tested negative does not have the virus is 89820/89832= 0.999 or about 99.9%.

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
I suspect that the answer may end up being almost the same, but
why do you start assuming that you have a population where
180 people are infected and 99800 are uninfected?
That would be a total of 180%2B99800=99980 ,
and the ratio of infected to total would be
180%2F99980=18%2F9998=approximately18%2F9999=2%2F1111=1%2F555.5 .
That means 1 person out of 555.5 people would be infected,
and that counts as a mistake.

You could have started with 100,000 people.
Of those, 100000%2F500=200 are infected,
and the remaining 100000-200=99800 are uninfected.
Of the 200 infected people,
0.1%28200%29=20 will test negative.
Of the 99800 uninfected,
0.9%2899800%29=89820 will test negative, as you said.
The total number of people testing negative is
20%2B89820=89840 .
Comparing to that number, the number of uninfected people is
89820%2F89840=0.999777 (rounded), which could be stated as highlight%28%2299.98%25%22%29 .

NOTES:
With your calculation you should get
89820%2F89838=0.999800 (rounded), which could be stated as 99.98%.
You mistakenly wrote your final calculation as
89820%2F89832=0.999866 (rounded), which could be stated as 99.99%.
Neither of those numbers can be rounded to 99.9%;
they would round to 100.0% if we only give them one decimal digit.

Note that before the test,
a person knew that the probability of being uninfected was
499%2F500=0.998000 or 99.80%.
If this virus is life-threatening (or life-altering),
people may want to know more.
If they test positive, maybe there is something they can do about it.
If they test negative,
going from 99.80% to 99.98% sure that they are safe may be cause for celebration.