Question 1061844: (4x-3)^2=-81,Solve for x
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! (4x-3)^2=-81,Solve for x
square toots of both sides
4x-3=+/-9i
4x-3+9i
4x=3+9i
x=(1/4)(3+9i)
x=(1/4)(3-9i)
Longer way is to foil it out and use the quadratic formula.
16x^2-24x+9+81=0
16x^2-24x+90=0
8x^2-12x+45=0
x=(1/16)(12+/-sqrt (144-1440); sqrt (-1296)=-36i
x=(1/16)(12+36i), or (1/4)(3+9i)
x=(1/16)(12-36i) or (1/4)((3-9i)
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