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Question 1061734: 1-Find the equation of the line perpendicular to the line whose equation is 2y-4x=7 and which passes through the point (1,2)
2-Given 3y-4x=5 and 4y+6=3x.Are these lines parallel,perpendicular,or neither?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 1-Find the equation of the line perpendicular to the line whose equation is
2y-4x=7 and which passes through the point (1,2)
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Slope of the given equation::
y = 2x + (7/2)
slope = 2
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Slope of the perpendicular line::
slope = -1/2
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Answer form:: y = mx + b
Solve for "b":
2 = (-1/2)1 + b
b = 2 1/2 = (5/2)
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Answer:: y = (-1/2)x + (5/2)
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2-Given 3y-4x=5 and 4y+6=3x.Are these lines parallel,perpendicular,or neither?
3y-4x = 5 DATA:
y = (4/3)x + (5/3)
slope = 4/3 ; intercept = (5/3)
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4y+6 = 3x DATA:
y = (3/4)x - (3/2)
slope = 3/4 ; intercept = (-3/2)
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Answer:: not perpendicular ; not parallel ; neither
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Cheers,
Stan H.
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