SOLUTION: can someone help me simplify 5√-32/5√243 please not sure how to. thank you in advance really grateful

Algebra ->  Square-cubic-other-roots -> SOLUTION: can someone help me simplify 5√-32/5√243 please not sure how to. thank you in advance really grateful       Log On


   

Question 1061724: can someone help me simplify 5√-32/5√243 please not sure how to.
thank you in advance really grateful
Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
I am assuming the problem is 5*sqrt(-32)/5* sqrt (243). Cancel the 5 right away
The numerator is i sqrt(32), but sqrt (32)=sqrt (16)*sqrt (2)=4 sqrt (2)
4i sqrt (2)
divided by sqrt (243)
243=3^5
Therefore sqrt (3^5) is sqrt (3*3*3*3*3)=3*3*sqrt (3)=9 sqrt (3)
The answer is
4i sqrt (2)/9 sqrt (3)
rationalize the denominator by multiplying top and bottom by sqrt (3)
4i sqrt(6)/9*3
4i sqrt (6)/27

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
can someone help me simplify 5√-32/5√243 please not sure how to.
thank you in advance really grateful 
You have to do a better job of presenting the problem. It's quite vague.

Anyway, I'm assuming it's: %28root+%285%2C+-+32%29%29%2Froot%285%2C+243%29. If so, then it becomes: highlight_green%28matrix%281%2C3%2C+%28-+2%29%2F3%2C+or%2C+-+2%2F3%29%29