SOLUTION: at a concession stand, five hot dogs and two hamburgers cost $8.50, two hot dogs and five hamburger cost $10.75. find the cost of one hot dog and the cost of one hamburger

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: at a concession stand, five hot dogs and two hamburgers cost $8.50, two hot dogs and five hamburger cost $10.75. find the cost of one hot dog and the cost of one hamburger      Log On


   

Question 1061569: at a concession stand, five hot dogs and two hamburgers cost $8.50, two hot dogs and five hamburger cost $10.75. find the cost of one hot dog and the cost of one hamburger
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
Make hotdogs = x
Hamburgers = y
5x + 2y = 8.50......Eq(1)
2x + 5y = 10.75.....Eq(2)
Multiply Eq(1) by 2 and Eq(2) by 5
10x + 4y = 17.......Eq(1)
10x + 25y = 53.75.....Eq(2)
Subtract Eq(1) from Eq(2)
....21y = 36.75
......y = 1.75
Substitute y = 1.75 in Eq(2)
2x + 5y = 10.75.....Eq(2)
2x + 5(1.75) = 10.75
2x + 8.75 = 10.75
2x = 10.75 - 8.75
2x = 2
x = 1
Hotdog costs $1
Hamburger costs $1.75
Hope this helps :-)