SOLUTION: the length of a rectangle is one more than twice its width. The area is 66ft squared/ how would I find the length and the width? Thank you!
Algebra ->
Rectangles
-> SOLUTION: the length of a rectangle is one more than twice its width. The area is 66ft squared/ how would I find the length and the width? Thank you!
Log On
Question 1061406: the length of a rectangle is one more than twice its width. The area is 66ft squared/ how would I find the length and the width? Thank you! Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! L = 2W+1
Area = 66
formula for area: L*W substitute for L:
(2W+1)*W = 66
from here we can solve using several methods. I'll use the factor method.
w*2W+W = 66
W^2*2+W = 66
W^2*2+W-66 = 0
2W^2+W-66 = 0 Factor the left side (FOIL):
(W+6)(2W-11) = 0
W+6 = 0 or 2W-11 = 0
W = -6 or W = 11/2 = 5.5
We are not looking for a negative number, so let's try 5.5:
W = 5.5 and L = 2W+1 = 2(5.5)+1 = 12
Area : 5.5*12 = 66 Correct.
:
John
