SOLUTION: Write an equation in slope intercept form that passes trough the point (1,-6) and is parallel to the equation x-2y=4. Then write an equation that passes trough the same point but i

Algebra ->  Graphs -> SOLUTION: Write an equation in slope intercept form that passes trough the point (1,-6) and is parallel to the equation x-2y=4. Then write an equation that passes trough the same point but i      Log On


   

Question 1061290: Write an equation in slope intercept form that passes trough the point (1,-6) and is parallel to the equation x-2y=4. Then write an equation that passes trough the same point but is perpendicular to the same equation.
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
For the given line:
+-2y+=+4+-+x+
+++y+=+%281%2F2%29x+-+2+ so slope is 1/2
Parallel line will have slope = 1/2:
++y+=+%281%2F2%29x+%2B+b+
This line passes through (1,-6) (x=1, y=-6), use this to find 'b':
+-6+=+%281%2F2%29%281%29+%2B+b+
+++b+=+-%2813%2F2%29+
—
Equation of parallel line is:
++y+=+%281%2F2%29x+-+%2813%2F2%29+
————————
Perpendicular lines have slopes that are negative reciprocals: so if m is the slope of one line, then -1/m is the slope of a line perpendicular to it.
y+=+%28%28-1%29%2F%281%2F2%29%29+x+%2B+b+
+y+=++%28-2%29x+%2B+b+
Find b using the same technique as above (1,-6) ==> y=-6 when x=1:
Then solve for b then re-write the equation of the line in final form.