Question 1061166: I'm not sure how to properly set this problem up as a system of linear equations:
Express the problem below as a system of linear equations and find the solution. Admission for a school play was $10 for adults and $5 for children. A total of 300 tickets were sold. How many adult tickets were sold if $2500 was collected at the door?
Found 3 solutions by josgarithmetic, addingup, MathTherapy:
Answer by josgarithmetic(39630)   (Show Source):
You can put this solution on YOUR website! Admission for a school play was $10 for adults and $5 for children. A total of 300 tickets were sold. How many adult tickets were sold if $2500 was collected at the door?
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Identify what are unknown.
y, Number of adult tickets
x, Number of child tickets
Account for the number of tickets.
x+y=300
Account for the sales revenue collected.
5x+10y=2500
The system of equations to solve is  .
Answer by addingup(3677)  (Show Source):
You can put this solution on YOUR website! a+c = 300 subtract c from both sides
a = 300-c
and
10a+5c = 2,500
10(300-c)+5c = 2,500
3,000-10c+5c = 2,500
-5c = -500
c = 100 these are the children's tickets that were sold
a = 300-100 = 200 this is how many adult tickets they sold
Answer by MathTherapy(10557)  (Show Source):
You can put this solution on YOUR website! I'm not sure how to properly set this problem up as a system of linear equations:
Express the problem below as a system of linear equations and find the solution. Admission for a school play was $10 for adults and $5 for children. A total of 300 tickets were sold. How many adult tickets were sold if $2500 was collected at the door?
Let number of adults' and children's tickets be A, and C, respectively
Then we get: 10A + 5C = 2,500_____5(2A + C) = 5(500)_____2A + C = 500 ------ eq (i)
Also, A + C = 300 ------- eq (ii)
If you wish to go further, just SUBTRACT eq (ii) from eq (i), and solve for A to get the number of adults' tickets sold.
It is that easy....nothing COMPLEX!!
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