SOLUTION: maximize Q=xy where x and y are positive numbers such that x+6y^2=2
The maximum value of Q is___ and occurs at x=__ and y=__
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The maximum value of Q is___ and occurs at x=__ and y=__
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Question 1061119: maximize Q=xy where x and y are positive numbers such that x+6y^2=2
The maximum value of Q is___ and occurs at x=__ and y=__ Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! x +6y^2 = 2
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6y^2 = -x +2
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y^2 = (-x/6) + (1/3)
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y = ( (-x/6) + (1/3) )^(1/2)
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this is a parabola that opens to the left
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the y intercept is (1/3)^(1/2) and x intercept is 2
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Here is the graph showing the positive values for x and y
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max value of Q is 2 * (1/3)^(1/2) = 1.1547 where x=2, y = (1/3)^(1/2)
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