SOLUTION: Determine, without graphing, whether the given quadratic function has a maximum value or a minimum value and then find that value. f(x) = -x^2 - 2x + 2 a. minimum; - 1

Algebra ->  Functions -> SOLUTION: Determine, without graphing, whether the given quadratic function has a maximum value or a minimum value and then find that value. f(x) = -x^2 - 2x + 2 a. minimum; - 1       Log On


   



Question 1061026: Determine, without graphing, whether the given quadratic function has a maximum value or a minimum value and then find that value.
f(x) = -x^2 - 2x + 2
a. minimum; - 1
b. maximum; 3
c. minimum; 3
d. maximum; - 1

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Coefficient on the degree-two term is negative one, -1, so the graph for the parabola is concave downward and has vertex as a MAXIMUM.

You could convert f into standard form and read the point for the vertex.

-x%5E2-2x%2B2
-%28x%5E2%2B2x-2%29
-%28x%5E2%2B2x%2B1-1-2%29------this step is Completing The Square.
-%28%28x%2B1%29%5E2-3%29
-%28x%2B1%29%5E2%2B3
Vertex is (-1,3).

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Determine, without graphing, whether the given quadratic function has a maximum value or a minimum value and then find that value.
f(x) = -x^2 - 2x + 2
a. minimum; - 1
b. maximum; 3
c. minimum; 3
d. maximum; - 1
Leading coefficient is < 0, so function has a highlight_green%28matrix%281%2C2%2C+MAXIMUM%2C+VALUE%29%29
That maximum value occurs at:
Therefore, maximum value is at f(- 1), and:
We then get: highlight_green%28matrix%281%2C2%2C+CHOICE%2C+%22b.%22%29%29
That's all.......nothing too COMPLEX!