SOLUTION: I'm not sure how to set up this problem.
a) Evaluate the expression in part (a) without using a calculator.
a) Use your result from part (a) to write the expression in part (
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: I'm not sure how to set up this problem.
a) Evaluate the expression in part (a) without using a calculator.
a) Use your result from part (a) to write the expression in part (
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Question 1060994: I'm not sure how to set up this problem.
a) Evaluate the expression in part (a) without using a calculator.
a) Use your result from part (a) to write the expression in part (b) as a single logarithm whose coefficient is 1.
91.) a) (log25)5
-For this I got 1/2
which is correct.
b.) (log25)x + (log25)(x^2-1) - (log25)(x+1) - 1/2
Really not sure what to do here.
But the answer in the book is two equivalent logarithmic expressions (separated by an equal sign.) Found 4 solutions by Alan3354, Theo, josmiceli, rothauserc:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! a) Evaluate the expression in part (a) without using a calculator.
a) Use your result from part (a) to write the expression in part (b) as a single logarithm whose coefficient is 1.
91.) a) (log25)5
-For this I got 1/2
which is correct.
============
Then why mention it?
5 is the sqrt(25) --? 5 = 25^(1/2)
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b.) (log25)x + (log25)(x^2-1) - (log25)(x+1) - 1/2
This is part b.
What is it you want to do?
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Really not sure what to do here.
But the answer in the book is two equivalent logarithmic expressions (separated by an equal sign.)
i checked that answer out by evaluating the original expression and the final expression and i got the same answer, so i'm reasonably certain it's correct.
i don't see this as an equation.
it's just an expression.
if you let me know what the answer is supposed to be, i can probably figure out how they got it.
You can put this solution on YOUR website! Here's the trick:
You already said
Take the reverse of this and plug it into
your 2nd equation:
Now use the rules:
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check the answer:
In the original equation, I'll say ,
because numbers work out good
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It can also be:
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Now I'll check the answer:
OK
Hope I got it!