SOLUTION: If logx-log(2x-1)is equal to 1,find x

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Question 1060876: If logx-log(2x-1)is equal to 1,find x
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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If logx-log(2x-1)is equal to 1,find x
Combine into a single log
log%28%28x%2F%282x-1%29%29%29+=+1
find the antilog of both sides
%28x%2F%282x-1%29%29+=+10
multiply both sides (2x-1)
x = 10(2x-1)
x = 20x - 10
10 = 20x - x
10 = 19x
x = 10%2F19
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Check on you your calc enter
log(10/19) - log(2(10/19)-1)) =